xmlNode to objects

Maybe this is too late to answer here but it will help others:

Here is the solution you will be able to Deserialize from the XML node.

 XmlDocument xmlDoc = new XmlDocument();
 xmlDoc.LoadXml(xml);

 XmlNode xmlNode = xmlDoc.SelectSingleNode("//SystemInfo");

 XmlSerializer serial = new XmlSerializer(typeof(SystemInfo));
 
 using(XmlNodeReader reader = new XmlNodeReader(xmlNode)) {
     SystemInfo syso =(SystemInfo)serial.Deserialize(reader);
 }

The first load the XML to XmlDocument Object and then find the parent node you will wish to deserialize just like I want SystemInfo object node from all the XML document.

Once you find that create an XmlSerializer object with the specific class type you will wish to.

Now just pass the reader (created with using) to the Deserialize method, you will get the objects populated in the class object just like I populated syso object with XML values.

Happy Coding :)

If you have the WCF Rest Starter Kit preview installed, there's a neat trick:

• open Visual Studio
• select your XML node contents (the XML that makes up one of your nodes) and copy it to the clipboard
• from your "Edit" menu in Visual Studio, pick "Paste XML as Types"

This will paste your XML that's on the clipboard into your project as a C# class that is capable of deserializing that exact XML. Pretty nifty!

See these blog posts about it:

• Aaron Skonnard: WCF REST Starter Kit: Paste XML as Types
• "Paste XML as Types" in REST Starter Kit

That should save you a lot of typing and make life a lot easier!

UPDATE:
OK, you already have your classes generated from the XML you get back. Now you need to convert a XmlNode to your class.

You'll have to do something like this:

private static T ConvertNode<T>(XmlNode node) where T: class
{
    MemoryStream stm = new MemoryStream();

    StreamWriter stw = new StreamWriter(stm);
    stw.Write(node.OuterXml);
    stw.Flush();

    stm.Position = 0;

    XmlSerializer ser = new XmlSerializer(typeof(T));
    T result = (ser.Deserialize(stm) as T);

    return result;
}

You need to write the XML representation (property .OuterXml) of the XmlNode to a stream (here a MemoryStream) and then use the XmlSerializer to serialize back the object from that stream.

You can do it with the generic method and call

 Customer myCustomer = ConvertNode<Customer>(xmlNode);

or you could even turn that code into either an extension method on the XmlNode class so you could write:

 Customer myCustomer = xmlNode.ConvertNode<Customer>();

Marc