Xor of binary strings in java

I would do it like this

private static boolean bitOf(char in) {
    return (in == '1');
}

private static char charOf(boolean in) {
    return (in) ? '1' : '0';
}

public static void main(String[] args) {
    String lseq ="0011111111101111111111111100101101111100110000001011111000010100";
    String tseq ="0011111111100000110011001100110011001100110011001100110011001100";
    String hseq ="0011111111110010010111110100010111100000101101001110000100011110";

    StringBuilder sb = new StringBuilder();

    for (int i = 0; i < lseq.length(); i++) {
        sb.append(charOf(bitOf(lseq.charAt(i)) ^ bitOf(tseq.charAt(i))
                ^ bitOf(hseq.charAt(i))));
    }

    String result = sb.toString();
    System.out.println(result);
}

Which outputs

0011111111111101011011000100001001010000101110001001001111000110