Integral of $\sin^5x\cdot\cos^{14}x$

It is in fact $u=-\cos x$ and by substitution we get $$\frac{1}{15}u^{15}-\frac{2}{17}u^{17}+\frac{1}{19}u^{19}\Bigg|_{-1}^0={1\over 15}-{2\over 17}+{1\over 19}={8\over 4845}$$You where only wrong in substitution...

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Integration

Definite Integrals

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