Intl.NumberFormat either 0 or two fraction digits
You could try something like this:
formatter.format(amount).replace(/\D00$/, '');
Update:
In response to the many-months-later comment by @Marek, the above regex already handles differing decimal symbols (either . or ,), but it's true that it doesn't handle trailing currency symbols. That can be fixed this way:
formatter.format(amount).replace(/\D00(?=\D*$)/, '');
The correct way to do it when using Intl.NumberFormat is to set both maximumFractionDigits and minimumFractionDigits options in constructor while validating input value using a modulo % for a whole number (per https://stackoverflow.com/a/49724586/1362535 which is a CORRECT answer!). The accepted answer is sort of string manipulation.
const fraction = new Intl.NumberFormat('en-NZ', {
style: 'currency',
currency: 'NZD',
minimumFractionDigits: 0,
maximumFractionDigits: 0,
});
const formatter = new Intl.NumberFormat('en-NZ', {
style: 'currency',
currency: 'NZD',
minimumFractionDigits: 2,
});
let number = 4.1;
if(number % 1 == 0)
console.log(fraction.format(number));
else
console.log(formatter.format(number));
number = 4;
if(number % 1 == 0)
console.log(fraction.format(number));
else
console.log(formatter.format(number));I would implement two different formats and validate it using a modulo %
4 % 1 == 0
4.1 % 1 == .1
Hope this helps :)
const formatter = new Intl.NumberFormat('en-NZ', {
style: 'currency',
currency: 'NZD',
minimumFractionDigits: 2,
});
const fraction = new Intl.NumberFormat('en-NZ', {
style: 'currency',
currency: 'NZD',
minimumFractionDigits: 0,
});
let number = 4.1;
if(number % 1 == 0)
console.log(fraction.format(number));
else
console.log(formatter.format(number));
number = 4;
if(number % 1 == 0)
console.log(fraction.format(number));
else
console.log(formatter.format(number));