Inverse Function (and WolframAlpha gives different Result)

Nothing wrong with your answer! Actually Wolfram's answer is wrong! Just check it by $x=3/2$ in wolfram's inverse.


Your error is in the solution formula. You have $(y+2)^2 - 4\cdot y\cdot 1 = y^2+4 \neq (y+2)(y-2)$. It would be $y^2-4 = (y+2)(y-2)$.

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Analysis

Real Analysis

Wolfram Alpha

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