'Inverted' border-radius possible?
if your element has only a background color, you may use pseudo-elements and box-shadow.
a hudge box-shadow on pseudo elements can fill the element. examples : http://codepen.io/gcyrillus/pen/hlAxo , http://codepen.io/gc-nomade/pen/dtnIv , http://codepen.io/gcyrillus/pen/yJfjl .
adding a linear gradient, you may draw a box similar to what you look for that can grow any heights : http://codepen.io/anon/pen/cIxwD .
div {
width:800px;
margin:auto;
position:relative;
overflow:hidden;
min-height:2000px;
background:linear-gradient(to bottom,
rgba(255,255,255,0) 0,
rgba(255,255,255,0) 100px,
orange 100px,
orange
);
}
div:before,
div:after
{
content:'';
position:absolute;
top:0;
height:30px;
width:60px;
box-shadow: 0 0 0 500px orange;
border-radius:0 0 0.5em 0;
}
div:after {
right:0;
border-radius: 0 0 0 0.5em;
}
Not using the native border-radius
. As mentioned on MDN "Negative values are invalid". You could definitely look for a library out there which does this for you automatically (though I find the approach taken in Philip's suggested library to be particularly outdated).
Using pure CSS I have come up with an approach. The idea is to add 4 extra elements inside your container, set their background to the same color as your page background (so this will not let page content underneath filter through – for that, you’d need SVG masking or similar), and to position
them in such a way that they lie just outside of the element itself. We then apply a border-radius
which gives the affect:
#main {
margin: 40px;
height: 100px;
background-color: #004C80;
position: relative;
overflow: hidden;
}
#main div {
position: absolute;
width: 20px;
height: 20px;
border-radius: 100%;
background-color: #FFF;
}
.top { top: -10px; }
.bottom { bottom: -10px; }
.left { left: -10px; }
.right { right: -10px; }
<div id="main">
<div class="top left"></div>
<div class="top right"></div>
<div class="bottom left"></div>
<div class="bottom right"></div>
</div>