iOS get Keyboard Window
I also had this problem and found the solution.
Below is the code which will work for iOS 8.0 and also for below versions.
I have tested it on iOS 7 and 8.0 (Xcode Version 6.0.1)
- (void)addButtonToKeyboard
{
// create custom button
self.doneButton = [UIButton buttonWithType:UIButtonTypeCustom];
self.doneButton.frame = CGRectMake(0, 163+44, 106, 53);
self.doneButton.adjustsImageWhenHighlighted = NO;
[self.doneButton setTag:67123];
[self.doneButton setImage:[UIImage imageNamed:@"doneup1.png"] forState:UIControlStateNormal];
[self.doneButton setImage:[UIImage imageNamed:@"donedown1.png"] forState:UIControlStateHighlighted];
[self.doneButton addTarget:self action:@selector(doneButton:) forControlEvents:UIControlEventTouchUpInside];
// locate keyboard view
int windowCount = [[[UIApplication sharedApplication] windows] count];
if (windowCount < 2) {
return;
}
UIWindow* tempWindow = [[[UIApplication sharedApplication] windows] objectAtIndex:1];
UIView* keyboard;
for(int i = 0 ; i < [tempWindow.subviews count] ; i++)
{
keyboard = [tempWindow.subviews objectAtIndex:i];
// keyboard found, add the button
if([[keyboard description] hasPrefix:@"<UIPeripheralHost"] == YES){
UIButton* searchbtn = (UIButton*)[keyboard viewWithTag:67123];
if (searchbtn == nil)//to avoid adding again and again as per my requirement (previous and next button on keyboard)
[keyboard addSubview:self.doneButton];
}//This code will work on iOS 8.0
else if([[keyboard description] hasPrefix:@"<UIInputSetContainerView"] == YES){
for(int i = 0 ; i < [keyboard.subviews count] ; i++)
{
UIView* hostkeyboard = [keyboard.subviews objectAtIndex:i];
if([[hostkeyboard description] hasPrefix:@"<UIInputSetHost"] == YES){
UIButton* donebtn = (UIButton*)[hostkeyboard viewWithTag:67123];
if (donebtn == nil)//to avoid adding again and again as per my requirement (previous and next button on keyboard)
[hostkeyboard addSubview:self.doneButton];
}
}
}
}
}
>
-(void) removedSearchButtonFromKeypad{
int windowCount = [[[UIApplication sharedApplication] windows] count];
if (windowCount < 2) {
return;
}
UIWindow* tempWindow = [[[UIApplication sharedApplication] windows] objectAtIndex:1];
for(int i = 0 ; i < [tempWindow.subviews count] ; i++)
{
UIView* keyboard = [tempWindow.subviews objectAtIndex:i];
if([[keyboard description] hasPrefix:@"<UIPeripheralHost"] == YES){
[self removeButton:keyboard];
}else if([[keyboard description] hasPrefix:@"<UIInputSetContainerView"] == YES){
for(int i = 0 ; i < [keyboard.subviews count] ; i++)
{
UIView* hostkeyboard = [keyboard.subviews objectAtIndex:i];
if([[hostkeyboard description] hasPrefix:@"<UIInputSetHost"] == YES){
[self removeButton:hostkeyboard];
}
}
}
}
}
-(void) removeButton:(UIView*)keypadView{
UIButton* donebtn = (UIButton*)[keypadView viewWithTag:67123];
if(donebtn){
[donebtn removeFromSuperview];
donebtn = nil;
}
}
Hope this helps.
What i use to get the window for the keyboard is
- (void)findKeyboardWindow
{
for (UIWindow *window in [[UIApplication sharedApplication] windows])
{
if ([NSStringFromClass([window class]) isEqualToString:@"UITextEffectsWindow"])
{
_keyboardWindow = window;
break;
}
}
}
From my logs on iOS8 this contains one view
UIInputSetContainerView: 0x190d4430; frame = (0 0; 320 568); autoresize = W+H; layer = CALayer: 0x190d4630
Which contains another view
UIInputSetHostView: 0x190d4820; frame = (0 352; 320 216); layer = CALayer: 0x190d49c0
Since those dimensions are 216.0f height i guess that is the keyboard. Was this what you where looking for?