Is Constructor Overriding Possible?

You can have many constructors as long as they take in different parameters. But the compiler putting a default constructor in is not called "constructor overriding".

It is never possible. Constructor Overriding is never possible in Java.

This is because,

Constructor looks like a method but name should be as class name and no return value.

Overriding means what we have declared in Super class, that exactly we have to declare in Sub class it is called Overriding. Super class name and Sub class names are different.

If you trying to write Super class Constructor in Sub class, then Sub class will treat that as a method not constructor because name should not match with Sub class name. And it will give an compilation error that methods does not have return value. So we should declare as void, then only it will compile.

---

Have a look at the following code :

Class One
        {
         ....
         One() { // Super Class constructor
          .... 
        }

        One(int a) { // Super Class Constructor Overloading
          .... 
        }
 }

Class Two extends One
                   {
                    One() {    // this is a method not constructor 
                    .....      // because name should not match with Class name
                   }

                    Two() { // sub class constructor
                   ....  
                   }

                   Two(int b) { // sub class constructor overloading
                   ....
                  }
 }  

What you describe isn't overriding. If you don't specify a default constructor, the compiler will create a default constructor. If it's a subclass, it will call the default parent constructor(super()), it will also initialize all instance variables to a default value determined by the type's default value(0 for numeric types, false for booleans, or null for objects).

Overriding happens when a subclass has the same name, number/type of parameters, and the same return type as an instance method of the superclass. In this case, the subclass will override the superclass's method. Information on overriding here.

Constructors are not normal methods and they cannot be "overridden". Saying that a constructor can be overridden would imply that a superclass constructor would be visible and could be called to create an instance of a subclass. This isn't true... a subclass doesn't have any constructors by default (except a no-arg constructor if the class it extends has one). It has to explicitly declare any other constructors, and those constructors belong to it and not to its superclass, even if they take the same parameters that the superclass constructors take.

The stuff you mention about default no arg constructors is just an aspect of how constructors work and has nothing to do with overriding.