Is it possible to go into ipython from code?
In IPython 0.11, you can embed IPython directly in your code like this
Your program might look like this
In [5]: cat > tmpf.py
a = 1
from IPython import embed
embed() # drop into an IPython session.
# Any variables you define or modify here
# will not affect program execution
c = 2
^D
This is what happens when you run it (I arbitrarily chose to run it inside an existing ipython session. Nesting ipython sessions like this in my experience can cause it to crash).
In [6]:
In [6]: run tmpf.py
Python 2.7.2 (default, Aug 25 2011, 00:06:33)
Type "copyright", "credits" or "license" for more information.
IPython 0.11 -- An enhanced Interactive Python.
? -> Introduction and overview of IPython's features.
%quickref -> Quick reference.
help -> Python's own help system.
object? -> Details about 'object', use 'object??' for extra details.
In [1]: who
a embed
In [2]: a
Out[2]: 1
In [3]:
Do you really want to exit ([y]/n)? y
In [7]: who
a c embed
There is an ipdb
project which embeds iPython into the standard pdb, so you can just do:
import ipdb; ipdb.set_trace()
It's installable via the usual pip install ipdb
.
ipdb
is pretty short, so instead of easy_installing you can also create a file ipdb.py
somewhere on your Python path and paste the following into the file:
import sys
from IPython.Debugger import Pdb
from IPython.Shell import IPShell
from IPython import ipapi
shell = IPShell(argv=[''])
def set_trace():
ip = ipapi.get()
def_colors = ip.options.colors
Pdb(def_colors).set_trace(sys._getframe().f_back)
If you're using a more modern version of IPython (> 0.10.2) you can use something like
from IPython.core.debugger import Pdb
Pdb().set_trace()
But it's probably better to just use ipdb