Is it possible to import modules from all files in a directory, using a wildcard?
I don't think this is possible, but afaik the resolution of module names is up to module loaders so there might a loader implementation that does support this.
Until then, you could use an intermediate "module file" at lib/things/index.js
that just contains
export * from 'ThingA';
export * from 'ThingB';
export * from 'ThingC';
and it would allow you to do
import {ThingA, ThingB, ThingC} from 'lib/things';
The current answers suggest a workaround but it's bugged me why this doesn't exist, so I've created a babel
plugin which does this.
Install it using:
npm i --save-dev babel-plugin-wildcard
then add it to your .babelrc
with:
{
"plugins": ["wildcard"]
}
see the repo for detailed install info
This allows you to do this:
import * as Things from './lib/things';
// Do whatever you want with these :D
Things.ThingA;
Things.ThingB;
Things.ThingC;
again, the repo contains further information on what exactly it does, but doing it this way avoids creating index.js
files and also happens at compile-time to avoid doing readdir
s at runtime.
Also with a newer version you can do exactly like your example:
import { ThingsA, ThingsB, ThingsC } from './lib/things/*';
works the same as the above.
You now can use async import():
import fs = require('fs');
and then:
fs.readdir('./someDir', (err, files) => {
files.forEach(file => {
const module = import('./' + file).then(m =>
m.callSomeMethod();
);
// or const module = await import('file')
});
});
Just a variation on the theme already provided in the answer, but how about this:
In a Thing
,
export default function ThingA () {}
In things/index.js
,
export {default as ThingA} from './ThingA'
export {default as ThingB} from './ThingB'
export {default as ThingC} from './ThingC'
Then to consume all the things elsewhere,
import * as things from './things'
things.ThingA()
Or to consume just some of things,
import {ThingA,ThingB} from './things'