Is it possible to import modules from all files in a directory, using a wildcard?

I don't think this is possible, but afaik the resolution of module names is up to module loaders so there might a loader implementation that does support this.

Until then, you could use an intermediate "module file" at lib/things/index.js that just contains

export * from 'ThingA';
export * from 'ThingB';
export * from 'ThingC';

and it would allow you to do

import {ThingA, ThingB, ThingC} from 'lib/things';

The current answers suggest a workaround but it's bugged me why this doesn't exist, so I've created a babel plugin which does this.

Install it using:

npm i --save-dev babel-plugin-wildcard

then add it to your .babelrc with:

{
    "plugins": ["wildcard"]
}

see the repo for detailed install info


This allows you to do this:

import * as Things from './lib/things';

// Do whatever you want with these :D
Things.ThingA;
Things.ThingB;
Things.ThingC;

again, the repo contains further information on what exactly it does, but doing it this way avoids creating index.js files and also happens at compile-time to avoid doing readdirs at runtime.

Also with a newer version you can do exactly like your example:

 import { ThingsA, ThingsB, ThingsC } from './lib/things/*';

works the same as the above.


You now can use async import():

import fs = require('fs');

and then:

fs.readdir('./someDir', (err, files) => {
 files.forEach(file => {
  const module = import('./' + file).then(m =>
    m.callSomeMethod();
  );
  // or const module = await import('file')
  });
});

Just a variation on the theme already provided in the answer, but how about this:

In a Thing,

export default function ThingA () {}

In things/index.js,

export {default as ThingA} from './ThingA'
export {default as ThingB} from './ThingB'
export {default as ThingC} from './ThingC'

Then to consume all the things elsewhere,

import * as things from './things'
things.ThingA()

Or to consume just some of things,

import {ThingA,ThingB} from './things'