is list pop python in place code example

Example 1: python pop element

my_list = [123, 'Add', 'Grepper', 'Answer']
my_list.pop()
-->[123, 'Add', 'Grepper'] #last element is removed

my_list = [123, 'Add', 'Grepper', 'Answer']
my_list.pop(0)
-->['Add', 'Grepper', 'Answer'] #first element is removed

my_list = [123, 'Add', 'Grepper', 'Answer']
any_index_of_the_list = 2
my_list.pop(any_index_of_the_list)
-->[123, 'Add', 'Answer'] #element at index 2 is removed 
						  #(first element is 0)

Example 2: python pop

# Python list method pop() removes
# and returns last object or obj from the list.
# .pop() last element .pop(0) first element

my_list = [123, 'Add', 'Grepper', 'Answer'];
print "Pop default: ", my_list.pop()
> Pop default:  Answer
# List updated to [123, 'Add', 'Grepper']
print "Pop index: ", my_list.pop(1)
> Pop index: Add
# List updated to [123, 'Grepper']