is templates class in c++ code example

Example 1: c++ template

#include <iostream>
using namespace std;

template <typename T>
void Swap(T &n1, T &n2)
{
	T temp;
	temp = n1;
	n1 = n2;
	n2 = temp;
}

int main()
{
	int i1 = 1, i2 = 2;
	float f1 = 1.1, f2 = 2.2;
	char c1 = 'a', c2 = 'b';

	cout << "Before passing data to function template.\n";
	cout << "i1 = " << i1 << "\ni2 = " << i2;
	cout << "\nf1 = " << f1 << "\nf2 = " << f2;
	cout << "\nc1 = " << c1 << "\nc2 = " << c2;

	Swap(i1, i2);
	Swap(f1, f2);
	Swap(c1, c2);

        cout << "\n\nAfter passing data to function template.\n";
	cout << "i1 = " << i1 << "\ni2 = " << i2;
	cout << "\nf1 = " << f1 << "\nf2 = " << f2;
	cout << "\nc1 = " << c1 << "\nc2 = " << c2;

	return 0;
}

Example 2: c++ class template

#include <vector>

// This is your own template
// T it's just a type
template <class T1, class T2, typename T3, typename T4 = int>
class MyClass
{
  public:
  	MyClass() { }
  
  private:
  	T1 data; 		// For example this data variable is T type
  	T2 anotherData;	// Actually you can name it as you wish but
  	T3 variable;	// for convenience you should name it T
}

int main(int argc, char **argv)
{
  std::vector<int> array(10);
  //          ^^^
  // This is a template in std library
  
  MyClass<int> object();
  // This is how it works with your class, just a template for type
  // < > angle brackets means "choose" any type you want
  // But it isn't necessary should work, because of some reasons
  // For example you need a type that do not supporting with class
  return (0);
}