Is there a clever way to use a small variable capacitor where a larger capacitance is required?

You could try an op-amp capacitance multiplier circuit:

Opamp capacitance multiplier (Courtesy of Wikipedia)

C = C1 * R1 / R2, so adjust R1 / R2 to provide the level of multiplication desired. Note that some op-amps have trouble driving capacitive loads. So if you connect a significant-enough capacitance to the op-amp output, it may oscillate.

Edit: A variant to try is this one. It uses the LM102 to buffer the input current, mostly eliminating the "resistance factor" from the previous circuit. I have not tested it, but would be skeptical of it's performance with very small capacitances. Also note that since C1 is being driven by the LM101A, this is "capacitive loading" and some op-amps could oscillate in this configuration. Some experimentation would be required. (Courtesy Texas Instruments) TI LM101A Datasheet


Given your variable cap and your need for a fairly wide tuning range, I'm afraid you're out of luck. Consider: from your formula $$f=\frac{1}{2\pi\sqrt{LC}}$$ $$LC=\frac{1}{{(2\pi f)}^2} = 2.5\times 10^{-8}$$ so $$C=\frac{1}{L{(2\pi f)}^2} = \frac{2.5\times 10^{-8}}{L}$$ and for a 3 mH inductor $$C= 8.45\times 10^{-6}$$ If you pad your tuner with 8.5 uF, and assume 0 pF on the tuner, you'll get a nominal frequency of $$f=\frac{1}{2\pi\sqrt{LC}} = 1.0028356 kHz$$ Cranking up tuner to 350 pF will give $$f=\frac{1}{2\pi\sqrt{L(C+\Delta C)}}=1.0028562 \text{kHz}$$ Basically, unless you can get much bigger inductors, your capacitance range is just too small to be useful.

A capacitance multiplier may sound like a good idea, but as presented it is not applicable. The circuit shown does not produce a pure capacitance. Instead, it is the equivalent of

schematic

simulate this circuit – Schematic created using CircuitLab where C is the multiplied value. You will find that this is not exactly a useful circuit for what you want to do.


Simply stick some fixed capacitors in parallel with the variable capacitor until you get to the capacitance you need -- your tuning range will be limited, but the resistor analog of this is a common way of implementing a "fine trim" type of control that operates on some sort of control voltage.