Is there a generic Task.WaitAll?

I'm pretty sure it's a safe operation even with the warning, but if you really wanted to get around it a better option than creating your own implementation would be just to convert your tasks parameter into the type it wants:

Task.WaitAll(tasks.Cast<Task>().ToArray())

That kills the blue squiggles for me, lets me keep my tasks variable generic and doesn't force me to create a whole lot of new scary code that's ultimately unnecessary.

You can create an extension method to do this.

I do not know the exact implementation of WaitAll, but we can assume it waits for every item to complete:

static class TaskExtensions
{
    public static void WaitAll<T>(this Task<T>[] tasks)
    {
        foreach (var item in tasks)
        {
            item.Wait();
        }
    }
}

Then call, from your current code:

tasks.WaitAll();

Edit

The actual implementation is a bit more complex. I have omitted the code from this answer because it is fairly long.

http://pastebin.com/u30PmrdS

You can modify this to support generic tasks.

A generic method of Task.WaitAll would imply that all Tasks would have to return the same type which would be extremely limited usefulness. Writting something like that could be done manually (see Bas Brekelmans answer), but this wont allow ContinueWith or cancellation without alot of work.

A simple solution if you aren't using the array for anything else is

  .ToArray<Task>();

A BETTER AND SIMPLER ANSWER

Actually there IS a similar generic overload:

Task all = Task.WhenAll(tasks)

This is different in this it returns a Task that will complete after all tasks completed. so you can use await on it, or Wait(), whatever you want.

Look at the signature:

Overloads

--------- NON GENERIC OVERLOADS --------------

WhenAll(IEnumerable<Task>) Creates a task that will complete when all of the Task objects in an enumerable collection have completed.

WhenAll(Task[]) Creates a task that will complete when all of the Task objects in an array have completed.

--------- GENERIC OVERLOADS --------------

WhenAll<TResult>(IEnumerable<Task<TResult>>) Creates a task that will complete when all of the Task<TResult> objects in an enumerable collection have completed.

WhenAll<TResult>(Task<TResult>[]) Creates a task that will complete when all of the Task<TResult> objects in an array have completed.