Is there more than one occurrence of a power of two between twin primes?

No: if $n$ is odd, $3\mid 2^n+1$, and if $n$ is even, $3\mid 2^n-1$.

To see this, note that $2^n+1=2^n+1^n$, which is divisible by $2+1$ if $n$ is odd, while $2^{2k}-1=4^k-1^k$ is divisible by $4-1$.

More complicatedly:

• If $2^n-1$ is a (Mersenne) prime, then $n$ must be prime: if $p|n$, then $2^p-1|2^n-1$.
• If $2^n+1$ is a (Fermat) prime, then $n$ must be a power of $2$: if $n=pk$ with $p$ odd, then $2^k+1|2^n+1$.

The only $n$ which is both prime and a power of $2$ is $2$ itself. So the only twin primes surrounding a power of $2$ will surround $2^2=4$.

Just some basics. Twin primes use the last digits of 1 & 3, 7 & 9, and 9 & 1 5 is and exception to the general rule. The powers of 2 use the last digits of 2, 4, 6, and 8. The only valid powers of 2 will have the last digits of 2 and 8. 2^2 = 4 and 2^3 = 8. Lots of luck trying to find more of them.