Iterate over Worksheets, Rows, Columns
Try this,
from openpyxl import load_workbook
workbook = load_workbook('----------/dataset.xlsx')
sheet = workbook.active
row_count = sheet.max_row
for i in range(row_count):
print(sheet.cell(row=i, column=2).value)
Read the OpenPyXL Documentation
Iteration over all worksheets
in a workbook
, for instance:
for n, sheet in enumerate(wb.worksheets):
print('Sheet Index:[{}], Title:{}'.format(n, sheet.title))
Output:
Sheet Index:[0], Title: Sheet Sheet Index:[1], Title: Sheet1 Sheet Index:[2], Title: Sheet2
Iteration over all rows
and columns
in one Worksheet:
worksheet = workbook.get_sheet_by_name('Sheet')
for row_cells in worksheet.iter_rows():
for cell in row_cells:
print('%s: cell.value=%s' % (cell, cell.value) )
Output:
<Cell Sheet.A1>: cell.value=²234
<Cell Sheet.B1>: cell.value=12.5
<Cell Sheet.C1>: cell.value=C1
<Cell Sheet.D1>: cell.value=D1
<Cell Sheet.A2>: cell.value=1234
<Cell Sheet.B2>: cell.value=8.2
<Cell Sheet.C2>: cell.value=C2
<Cell Sheet.D2>: cell.value=D2
Iteration over all columns
of one row
, for instance row==2
:
for row_cells in worksheet.iter_rows(min_row=2, max_row=2):
for cell in row_cells:
print('%s: cell.value=%s' % (cell, cell.value) )
Output:
<Cell Sheet.A2>: cell.value=1234
<Cell Sheet.B2>: cell.value=8.2
<Cell Sheet.C2>: cell.value=C2
<Cell Sheet.D2>: cell.value=D2
Iteration over all rows
, only column
2:
for col_cells in worksheet.iter_cols(min_col=2, max_col=2):
for cell in col_cells:
print('%s: cell.value=%s' % (cell, cell.value))
Output:
<Cell Sheet.B1>: cell.value=12.5
<Cell Sheet.B2>: cell.value=8.2
<Cell Sheet.B3>: cell.value=9.8
<Cell Sheet.B4>: cell.value=10.1
<Cell Sheet.B5>: cell.value=7.7
Tested with Python:3.4.2 - openpyxl:2.4.1 - LibreOffice: 4.3.3.2