Iterating over two lists one after another

This can be done with itertools.chain:

import itertools

l1 = [1, 2, 3, 4]
l2 = [5, 6, 7, 8]

for i in itertools.chain(l1, l2):
    print(i, end=" ")

Which will print:

1 2 3 4 5 6 7 8 

As per the documentation, chain does the following:

Make an iterator that returns elements from the first iterable until it is exhausted, then proceeds to the next iterable, until all of the iterables are exhausted.

If you have your lists in a list, itertools.chain.from_iterable is available:

l = [l1, l2]
for i in itertools.chain.from_iterable(l):
    print(i, end=" ")

Which yields the same result.

If you don't want to import a module for this, writing a function for it is pretty straight-forward:

def custom_chain(*it):
    for iterab in it:
        yield from iterab

This requires Python 3, for Python 2, just yield them back using a loop:

def custom_chain(*it):
    for iterab in it:
        for val in iterab:
            yield val

In addition to the previous, Python 3.5 with its extended unpacking generalizations, also allows unpacking in the list literal:

for i in [*l1, *l2]:
    print(i, end=" ")

though this is slightly faster than l1 + l2 it still constructs a list which is then tossed; only go for it as a final solution.

chain works, but if you feel that it's overkill to import a module just to call a single function once, you can replicate its behavior inline:

for seq in (list1, list2):
  for item in seq:
    print(item.amount)
    print(item.total_amount)

Creating the (list1, list2) tuple is O(1) with respect to list length, so it should perform favorably in comparison to concatenating the lists together.