iterating over two values of a list at a time in python
>>> nums = (669256.02, 6117662.09, 669258.61, 6117664.39, 669258.05, 6117665.08)
>>> for x, y in zip(*[iter(nums)]*2):
print(x, y)
669256.02 6117662.09
669258.61 6117664.39
669258.05 6117665.08
You can use an iterator:
>>> lis = (669256.02, 6117662.09, 669258.61, 6117664.39, 669258.05, 6117665.08)
>>> it = iter(lis)
>>> for x in it:
... print (x, next(it))
...
669256.02 6117662.09
669258.61 6117664.39
669258.05 6117665.08
The grouper
example in the itertools
recipes section should help you here:
http://docs.python.org/library/itertools.html#itertools-recipes
from itertools import zip_longest
def grouper(iterable, n, fillvalue=None):
"Collect data into fixed-length chunks or blocks"
# grouper('ABCDEFG', 3, 'x') --> ABC DEF Gxx"
args = [iter(iterable)] * n
return zip_longest(*args, fillvalue=fillvalue)
You would then it use like this:
for x, y in grouper(my_set, 2, 0.0): # Use 0.0 to pad with a float
print(x, y)