Jackson @JsonFormat set date with one day less
@William's answer works but you should add theses lines to your application.properties files instead:
spring.jackson.time-zone=Brazil/East
spring.jackson.locale=pt-BR
In that way, you indicate the time-zone and locale only one time, and it applicate to all the Date of your application.
Use this solution, it is more effective and modern than my solution: https://stackoverflow.com/a/45456037/4886918
Thanks @Benjamin Lucidarme.
I resolved my problem using:
@Temporal(TemporalType.DATE)
@JsonFormat(shape = JsonFormat.Shape.STRING, pattern = "dd/MM/yyyy", locale = "pt-BR", timezone = "Brazil/East")
private Date birthDate;
I changed timezone to "Brazil/East" or "America/Sao_Paulo" and working now
Thanks
I'd go with setting ObjectMapper
timezone as default JVM timezone:
ObjectMapper objectMapper = new ObjectMapper();
//Set default time zone as JVM timezone due to one day difference between original date and formatted date.
objectMapper.setTimeZone(TimeZone.getDefault());
It's a better solution if you don't know what timezone is used on a server environment.
In spring-boot
environment you can override default JacksonAutoConfiguration
:
@Bean
ObjectMapper jacksonObjectMapper(Jackson2ObjectMapperBuilder builder) {
return builder.createXmlMapper(false)
// Set timezone for JSON serialization as system timezone
.timeZone(TimeZone.getDefault())
.build();
}
On both side (Client - Server) annotate your date filed like this:
@JsonDeserialize(using = JsonDateDeserializer.class)
@JsonSerialize(using = JsonDateSerializer.class)
private Date birthDate;
and on both side again put this implementations for serializing and deserializing:
public class JsonDateSerializer extends JsonSerializer<Date> {
SimpleDateFormat format = new SimpleDateFormat("dd/MM/yyyy");
@Override
public void serialize(final Date date, final JsonGenerator gen, final SerializerProvider provider) throws IOException, JsonProcessingException {
String dateString = format.format(date);
gen.writeString(dateString);
}
}
public class JsonDateDeserializer extends JsonDeserializer<Date> {
SimpleDateFormat format = new SimpleDateFormat("dd/MM/yyyy");
@Override
public Date deserialize(final JsonParser jp, final DeserializationContext ctxt) throws IOException, JsonProcessingException {
if (jp.getCurrentToken().equals(JsonToken.VALUE_STRING)) {
try {
Date date = format.parse(jp.getText().toString());
return date;
} catch (ParseException e) {
//e.printStackTrace();
}
}
return null;
}
}