4 digit ArmStrong number problem java code example
Example 1: Armstrong number in java
import java.util.Scanner;
public class ArmstrongNumber
{
public static void main(String[] args)
{
int x, y, z = 0, temp;
Scanner sc = new Scanner(System.in);
System.out.println("Please enter a number: ");
x = sc.nextInt();
temp = x;
while(x > 0)
{
y = x % 10;
x = x / 10;
z = z + (y * y * y);
}
if(temp == z)
{
System.out.println(temp + " is an Armstrong Number.");
}
else
{
System.out.println(temp + " is not an Armstrong Number.");
}
sc.close();
}
}
Example 2: 4 digit armstrong number in java
public class ArmstrongNumberDemo
{
public static void main(String[] args)
{
int num = 9474, realNumber, remainder, output = 0, a = 0;
realNumber = num;
for(;realNumber != 0; realNumber /= 10, ++a);
realNumber = num;
for(;realNumber != 0; realNumber /= 10)
{
remainder = realNumber % 10;
output += Math.pow(remainder, a);
}
if(output == num)
{
System.out.println(num + " is an Armstrong number.");
}
else
{
System.out.println(num + " is not an Armstrong number.");
}
}
}