armstrong number find in java for n digits code example

Example 1: armstrong number in java

int c=0,a,temp;  
    int n=153;//It is the number to check armstrong  
    temp=n;  
    while(n>0)  
    {  
    a=n%10;  
    n=n/10;  
    c=c+(a*a*a);  
    }  
    if(temp==c)  
    System.out.println("armstrong number");   
    else  
        System.out.println("Not armstrong number");

Example 2: armstrong number in java

import java.util.Scanner;

public class Armstrong
{
  public static void main(String args[])
  {
    int num,temp,c=0;
  	Scanner in=new Scanner(System.in);
  	num=in.nextInt();
  	temp=num;
  	while(num!=0)
  	{
    	int d=num%10; //extracting last digit
    	c+=d*d*d;
    	num/=10; // removing last digit
  	}
  	if(temp==c)
  	{
    	System.out.println("Number is Armstrong");
  	}
  	else
  		System.out.println("Number is not Armstrong");
  }
}