can you use a quicksort on strings java code example
Example 1: is it possible to quick sort a string in java
public class StringQuickSort {
String names[];
int length;
public static void main(String[] args) {
StringQuickSort sorter = new StringQuickSort();
String words[] = {"zz", "aa", "cc", "hh", "bb", "ee", "ll"}; // the strings need to be sorted are put inside this array
sorter.sort(words);
for (String i : words) {
System.out.print(i);
System.out.print(" ");
}
}
void sort(String array[]) {
if (array == null || array.length == 0) {
return;
}
this.names = array;
this.length = array.length;
quickSort(0, length - 1);
}
void quickSort(int lowerIndex, int higherIndex) {
int i = lowerIndex;
int j = higherIndex;
String pivot = this.names[lowerIndex + (higherIndex - lowerIndex) / 2];
while (i <= j) {
while (this.names[i].compareToIgnoreCase(pivot) < 0) {
i++;
}
while (this.names[j].compareToIgnoreCase(pivot) > 0) {
j--;
}
if (i <= j) {
exchangeNames(i, j);
i++;
j--;
}
}
//call quickSort recursively
if (lowerIndex < j) {
quickSort(lowerIndex, j);
}
if (i < higherIndex) {
quickSort(i, higherIndex);
}
}
void exchangeNames(int i, int j) {
String temp = this.names[i];
this.names[i] = this.names[j];
this.names[j] = temp;
}
}
Example 2: is it possible to quick sort a string in java
private static void quickSort(String[] a, int start, int end)
{
// index for the "left-to-right scan"
int i = start;
// index for the "right-to-left scan"
int j = end;
// only examine arrays of 2 or more elements.
if (j - i >= 1)
{
// The pivot point of the sort method is arbitrarily set to the first element int the array.
String pivot = a[i];
// only scan between the two indexes, until they meet.
while (j > i)
{
// from the left, if the current element is lexicographically less than the (original)
// first element in the String array, move on. Stop advancing the counter when we reach
// the right or an element that is lexicographically greater than the pivot String.
while (a[i].compareTo(pivot) < 0 && i <= end && j > i){
i++;
}
// from the right, if the current element is lexicographically greater than the (original)
// first element in the String array, move on. Stop advancing the counter when we reach
// the left or an element that is lexicographically less than the pivot String.
while (a[j].compareTo(pivot) > 0 && j >= start && j >= i){
j--;
}
// check the two elements in the center, the last comparison before the scans cross.
if (j > i)
swap(a, i, j);
}
// At this point, the two scans have crossed each other in the center of the array and stop.
// The left partition and right partition contain the right groups of numbers but are not
// sorted themselves. The following recursive code sorts the left and right partitions.
// Swap the pivot point with the last element of the left partition.
swap(a, start, j);
// sort left partition
quickSort(a, start, j - 1);
// sort right partition
quickSort(a, j + 1, end);
}
}
/**
* This method facilitates the quickSort method's need to swap two elements, Towers of Hanoi style.
*/
private static void swap(String[] a, int i, int j)
{
String temp = a[i];
a[i] = a[j];
a[j] = temp;
}