check number is armstrong or not in java code example
Example 1: Armstrong number in java
import java.util.Scanner;
public class ArmstrongNumber
{
public static void main(String[] args)
{
int x, y, z = 0, temp;
Scanner sc = new Scanner(System.in);
System.out.println("Please enter a number: ");
x = sc.nextInt();
temp = x;
while(x > 0)
{
y = x % 10;
x = x / 10;
z = z + (y * y * y);
}
if(temp == z)
{
System.out.println(temp + " is an Armstrong Number.");
}
else
{
System.out.println(temp + " is not an Armstrong Number.");
}
sc.close();
}
}
Example 2: armstrong number in java
int c=0,a,temp;
int n=153;
temp=n;
while(n>0)
{
a=n%10;
n=n/10;
c=c+(a*a*a);
}
if(temp==c)
System.out.println("armstrong number");
else
System.out.println("Not armstrong number");