display doubly linked list in reverse order in c code example
Example: reverse a singly linked list in c
#include <stdio.h>
#include <stdlib.h>
struct node {
int data;
struct node *next;
}*head;
void createList(int n);
void reverseList();
void displayList();
int main()
{
int n, choice;
printf("Enter the total number of nodes: ");
scanf("%d", &n);
createList(n);
printf("\nData in the list \n");
displayList();
printf("\nPress 1 to reverse the order of singly linked list\n");
scanf("%d", &choice);
if(choice == 1)
{
reverseList();
}
printf("\nData in the list\n");
displayList();
return 0;
}
void createList(int n)
{
struct node *newNode, *temp;
int data, i;
if(n <= 0)
{
printf("List size must be greater than zero.\n");
return;
}
head = (struct node *)malloc(sizeof(struct node));
if(head == NULL)
{
printf("Unable to allocate memory.");
}
else
{
printf("Enter the data of node 1: ");
scanf("%d", &data);
head->data = data;
head->next = NULL;
temp = head;
for(i=2; i<=n; i++)
{
newNode = (struct node *)malloc(sizeof(struct node));
if(newNode == NULL)
{
printf("Unable to allocate memory.");
break;
}
else
{
printf("Enter the data of node %d: ", i);
scanf("%d", &data);
newNode->data = data;
newNode->next = NULL;
temp->next = newNode;
temp = temp->next;
}
}
printf("SINGLY LINKED LIST CREATED SUCCESSFULLY\n");
}
}
void reverseList()
{
struct node *prevNode, *curNode;
if(head != NULL)
{
prevNode = head;
curNode = head->next;
head = head->next;
prevNode->next = NULL;
while(head != NULL)
{
head = head->next;
curNode->next = prevNode;
prevNode = curNode;
curNode = head;
}
head = prevNode;
printf("SUCCESSFULLY REVERSED LIST\n");
}
}
void displayList()
{
struct node *temp;
if(head == NULL)
{
printf("List is empty.");
}
else
{
temp = head;
while(temp != NULL)
{
printf("Data = %d\n", temp->data);
temp = temp->next;
}
}
}