for iterator python code example

Example 1: python return iteration number of for loop

# Basic syntax:
for iteration, item in enumerate(iteratable_object):
	print(iteration)
# Where:
#	- item is the current element in the iteratable_object
#	- iteration is the iteration number/count for the current iteration

# Basic syntax using list comprehension:
[iteration for iteration, item in enumerate(iteratable_object)]

# Example usage:
your_list = ["a", "b", "c", "d"]

for iteration,item in enumerate(your_list):
	(iteration, item) # Return tuples of iteration, item
--> (0, 'a')
	(1, 'b')
	(2, 'c')
	(3, 'd')

[iteration for iteration, item in enumerate(your_list)]
--> [0, 1, 2, 3]

Example 2: iterator in python

# define a list
my_list = [4, 7, 0, 3]

# get an iterator using iter()
my_iter = iter(my_list)

# iterate through it using next()

# Output: 4
print(next(my_iter))

# Output: 7
print(next(my_iter))

# next(obj) is same as obj.__next__()

# Output: 0
print(my_iter.__next__())

# Output: 3
print(my_iter.__next__())

# This will raise error, no items left
next(my_iter)

Example 3: iterator in python

class PowTwo:
    """Class to implement an iterator
    of powers of two"""

    def __init__(self, max=0):
        self.max = max

    def __iter__(self):
        self.n = 0
        return self

    def __next__(self):
        if self.n <= self.max:
            result = 2 ** self.n
            self.n += 1
            return result
        else:
            raise StopIteration


# create an object
numbers = PowTwo(3)

# create an iterable from the object
i = iter(numbers)

# Using next to get to the next iterator element
print(next(i))
print(next(i))
print(next(i))
print(next(i))
print(next(i))

Example 4: python iterator

pies = ["cherry", "apple", "pumpkin", "pecan"]

iterator = iter(pies)

print(next(iterator))
#prints "cherry" because it's the current one being iterated over

Example 5: python for loop iterator

import numpy as np
# With array cycling
arr = np.array([1,2,3,4,5,6,7,8,9])

for i in range(len(arr)):
 # logic with iterator use (current logic replaces even numbers with zero)
    if arr[i] % 2 == 0: arr[i] = 0

print(arr)
# Output: [1, 0, 3, 0, 5, 0, 7, 0 , 9]

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