how to find all non repeated characters in a string in java code example
Example 1: counting repeated characters in a string in java
void Findrepeter(){
String s="mmababctamantlslmag";
int distinct = 0 ;
for (int i = 0; i < s.length(); i++) {
for (int j = 0; j < s.length(); j++) {
if(s.charAt(i)==s.charAt(j))
{
distinct++;
}
}
System.out.println(s.charAt(i)+"--"+distinct);
String d=String.valueOf(s.charAt(i)).trim();
s=s.replaceAll(d,"");
distinct = 0;
}
}
Example 2: java, how to find the most repeated character
private static String findMaxChar(String str) {
char[] array = str.toCharArray();
Set<Character> maxChars = new LinkedHashSet<Character>();
int maxCount = 1;
maxChars.add(array[0]);
for(int i = 0, j = 0; i < str.length() - 1; i = j){
int count = 1;
while (++j < str.length() && array[i] == array[j]) {
count++;
}
if (count > maxCount) {
maxCount = count;
maxChars.clear();
maxChars.add(array[i]);
} else if (count == maxCount) {
maxChars.add(array[i]);
}
}
return (maxChars + " = " + maxCount);
}
Example 3: counting repeated characters in a string in java
import java.io.*;
public class CountChar
{
public static void main(String[] args) throws IOException
{
String ch;
BufferedReader br=new BufferedReader(new InputStreamReader(System.in));
System.out.print("Enter the Statement:");
ch=br.readLine();
int count=0,len=0;
do
{
try
{
char name[]=ch.toCharArray();
len=name.length;
count=0;
for(int j=0;j<len;j++)
{
if((name[0]==name[j])&&((name[0]>=65&&name[0]<=91)||(name[0]>=97&&name[0]<=123)))
count++;
}
if(count!=0)
System.out.println(name[0]+" "+count+" Times");
ch=ch.replace(""+name[0],"");
}
catch(Exception ex){}
}
while(len!=1);
}
}