how to runnable thread to executor pool code example
Example: java use thread pool executor
import java.util.concurrent.Executors;
import java.util.concurrent.ThreadPoolExecutor;
import java.util.concurrent.TimeUnit;
public class TestThread {
public static void main(final String[] arguments) throws InterruptedException {
ThreadPoolExecutor executor = (ThreadPoolExecutor)Executors.newCachedThreadPool();
System.out.println("Largest executions: "
+ executor.getLargestPoolSize());
System.out.println("Maximum allowed threads: "
+ executor.getMaximumPoolSize());
System.out.println("Current threads in pool: "
+ executor.getPoolSize());
System.out.println("Currently executing threads: "
+ executor.getActiveCount());
System.out.println("Total number of threads(ever scheduled): "
+ executor.getTaskCount());
executor.submit(new Task());
executor.submit(new Task());
System.out.println("Core threads: " + executor.getCorePoolSize());
System.out.println("Largest executions: "
+ executor.getLargestPoolSize());
System.out.println("Maximum allowed threads: "
+ executor.getMaximumPoolSize());
System.out.println("Current threads in pool: "
+ executor.getPoolSize());
System.out.println("Currently executing threads: "
+ executor.getActiveCount());
System.out.println("Total number of threads(ever scheduled): "
+ executor.getTaskCount());
executor.shutdown();
}
static class Task implements Runnable {
public void run() {
try {
Long duration = (long) (Math.random() * 5);
System.out.println("Running Task! Thread Name: " +
Thread.currentThread().getName());
TimeUnit.SECONDS.sleep(duration);
System.out.println("Task Completed! Thread Name: " +
Thread.currentThread().getName());
} catch (InterruptedException e) {
e.printStackTrace();
}
}
}
}