java program to find armstrong numbers code example

Example 1: Java program to print all armstrong numbers between given range

// Java program to print all armstrong numbers between given range
import java.util.Scanner;
public class ArmstrongNumbersGivenRange 
{
   public static void main(String[] args) 
   {
      int number, startNumber, endNumber, a, rem, n, count = 0;
      Scanner sc = new Scanner(System.in);
      System.out.println("Please enter starting number range: ");
      startNumber = sc.nextInt();
      System.out.println("Please enter ending number range: ");
      endNumber = sc.nextInt();
      for(a = startNumber + 1; a < endNumber; a++)
      {
         n = a;
         number = 0;
         while(n != 0)
         {
            rem = n % 10;
            number = number + rem * rem * rem;
            n = n / 10;
         }
         if(a == number)
         {
            if(count == 0)
            {
               System.out.println("Armstrong numbers between given range " + startNumber + " and " + endNumber + ": ");
            }
            System.out.print(a + "  ");
            count++;
         }
      }
      // if there is no Armstrong number found between range
      if(count == 0)
      {
         System.out.println("Sorry!! There's no armstrong number between given range " + startNumber + " and " + endNumber);
      }
      sc.close();
   }
}

Example 2: Armstrong number in java

// Check whether a given number is armstrong number or not
import java.util.Scanner;
public class ArmstrongNumber
{
   public static void main(String[] args)
   {
      int x, y, z = 0, temp;
      Scanner sc = new Scanner(System.in);
      System.out.println("Please enter a number: ");
      x = sc.nextInt();
      temp = x;
      while(x > 0)
      {
         y = x % 10;
         x = x / 10;
         z = z + (y * y * y);
      }
      if(temp == z)
      {
         System.out.println(temp + " is an Armstrong Number.");
      }
      else
      {
         System.out.println(temp + " is not an Armstrong Number.");
      }
      sc.close();
   }
}

Example 3: armstrong number in java

int c=0,a,temp;  
    int n=153;//It is the number to check armstrong  
    temp=n;  
    while(n>0)  
    {  
    a=n%10;  
    n=n/10;  
    c=c+(a*a*a);  
    }  
    if(temp==c)  
    System.out.println("armstrong number");   
    else  
        System.out.println("Not armstrong number");