Example 1: Merge sort in c++
#include <iostream>
using namespace std;
void merge(int arr[], int l, int m, int r)
{
int n1 = m - l + 1;
int n2 = r - m;
int L[n1], R[n2];
for (int i = 0; i < n1; i++)
L[i] = arr[l + i];
for (int j = 0; j < n2; j++)
R[j] = arr[m + 1 + j];
int i = 0;
int j = 0;
int k = l;
while (i < n1 && j < n2) {
if (L[i] <= R[j]) {
arr[k] = L[i];
i++;
}
else {
arr[k] = R[j];
j++;
}
k++;
}
while (i < n1) {
arr[k] = L[i];
i++;
k++;
}
while (j < n2) {
arr[k] = R[j];
j++;
k++;
}
}
void mergeSort(int arr[],int l,int r){
if(l>=r){
return;
}
int m = (l+r-1)/2;
mergeSort(arr,l,m);
mergeSort(arr,m+1,r);
merge(arr,l,m,r);
}
void printArray(int A[], int size)
{
for (int i = 0; i < size; i++)
cout << A[i] << " ";
}
int main()
{
int arr[] = { 12, 11, 13, 5, 6, 7 };
int arr_size = sizeof(arr) / sizeof(arr[0]);
cout << "Given array is \n";
printArray(arr, arr_size);
mergeSort(arr, 0, arr_size - 1);
cout << "\nSorted array is \n";
printArray(arr, arr_size);
return 0;
}
Example 2: merge sort
function merge(list, start, midpoint, end) {
const left = list.slice(start, midpoint);
const right = list.slice(midpoint, end);
for (let topLeft = 0, topRight = 0, i = start; i < end; i += 1) {
if (topLeft >= left.length) {
list[i] = right[topRight++];
} else if (topRight >= right.length) {
list[i] = left[topLeft++];
} else if (left[topLeft] < right[topRight]) {
list[i] = left[topLeft++];
} else {
list[i] = right[topRight++];
}
}
}
function mergesort(list, start = 0, end = undefined) {
if (end === undefined) {
end = list.length;
}
if (end - start > 1) {
const midpoint = ((end + start) / 2) >> 0;
mergesort(list, start, midpoint);
mergesort(list, midpoint, end);
merge(list, start, midpoint, end);
}
return list;
}
mergesort([4, 7, 2, 6, 4, 1, 8, 3]);
Example 3: merge sort algo
def mergeSort(arr):
if len(arr) >1:
mid = len(arr)
L = arr[:mid] # Dividing the array elements
R = arr[mid:] # into 2 halves
mergeSort(L) # Sorting the first half
mergeSort(R) # Sorting the second half
i = j = k = 0
# Copy data to temp arrays L[] and R[]
while i < len(L) and j < len(R):
if L[i] < R[j]:
arr[k] = L[i]
i+= 1
else:
arr[k] = R[j]
j+= 1
k+= 1
# Checking if any element was left
while i < len(L):
arr[k] = L[i]
i+= 1
k+= 1
while j < len(R):
arr[k] = R[j]
j+= 1
k+= 1
# Code to print the list
def printList(arr):
for i in range(len(arr)):
print(arr[i], end =" ")
print()
# driver code to test the above code
if __name__ == '__main__':
arr = [12, 11, 13, 5, 6, 7]
print ("Given array is", end ="\n")
printList(arr)
mergeSort(arr)
print("Sorted array is: ", end ="\n")
printList(arr)
Example 4: merge sort c++
#include "tools.hpp"
std::vector<int> sort(size_t start, size_t length, const std::vector<int>& vec)
{
if(vec.size()==0 ||vec.size() == 1)
return vec;
vector<int> left,right;
size_t mid_point = vec.size()/2;
for(int i = 0 ; i < mid_point; ++i){left.emplace_back(vec[i]);}
for(int j = mid_point; j < length; ++j){ right.emplace_back(vec[j]);}
left = sort(start,mid_point,left);
right = sort(mid_point,length-mid_point,right);
return merge(left,right);
}
vector<int> merge(const vector<int>& a, const vector<int>& b)
{
vector<int> merged_a_b(a.size()+b.size(),0);
int i = 0;
int j = 0;
int k = 0;
int left_size = a.size();
int right_size = b.size();
while(i<left_size && j<right_size)
{
if(a[i]<b[j])
{
merged_a_b[k]=a[i];
i++;
}
else
{
merged_a_b[k]=b[j];
j++;
}
k++;
}
while(i<left_size)
{
merged_a_b[k]=a[i];
i++;
k++;
}
while(j<right_size)
{
merged_a_b[k]=b[j];
j++;
k++;
}
return merged_a_b;
}