Java method with unlimited arguments
It's called varargs.
It allows a method to take any number of arguments. They are accessible as an array in the method:
public void foo(String... args) {
for (String arg : args) {
// do smth with arg.
}
}
This is syntactic sugar. The compiler hides the array creation, so instead of
bar.foo(new String[] {"1", "2", "3"});
you write
bar.foo("1", "2", "3");
To add the Bozho's answer, you can also have other arguments in your method before varargs:
// foo(13, "foo", "bar", "baz");
// will print:
// 13 - |foo||bar||baz|
public void foo(int a, String... b) {
System.out.println(a + " - ");
for (String c : b) {
System.out.print("|" + c + "|");
}
}
However you can not have arguments of a different type after. These do not work:
public void bar(String... b, int b);
public void foo(int a, String... b, int b);