javac not working in windows command prompt
If you added it in the control panel while your command prompt was open, that won't affect your current command prompt. You'll need to exit and re-open or simply do:
set "path=%path%;c:\program files\java\jdk1.6.0_16\bin"
By way of checking, execute:
echo %path%
from your command prompt and let us know what it is.
Otherwise, make sure there is a javac in that directory by trying:
"c:\program files\java\jdk1.6.0_16\bin\javac.exe"
from the command prompt. You can also tell which executable (if any) is being used with the command:
for %i in (javac.exe) do @echo %~$PATH:i
This is a neat trick similar to the which and/or whence commands in some UNIX-type operating systems.
Windows OS searches the current directory and the directories listed in the PATH environment variable for executable programs. JDK's programs (such as Java compiler javac.exe and Java runtime java.exe) reside in directory "\bin" (where denotes the JDK installed directory, e.g., C:\Program Files\Java\jdk1.8.0_xx). You need to include the "\bin" directory in the PATH.
To edit the PATH environment variable in Windows XP/Vista/7/8:
Control Panel ⇒ System ⇒ Advanced system settings
Switch to "Advanced" tab ⇒ Environment Variables
In "System Variables", scroll down to select "PATH" ⇒ Edit
(( now read the following 3 times before proceeding, THERE IS NO UNDO ))
In "Variable value" field, INSERT "c:\Program Files\Java\jdk1.8.0_xx\bin" (Replace xx with the upgrade number and VERIFY that this is your JDK's binary directory!!!) IN FRONT of all the existing directories, followed by a semi-colon (;) which separates the JDK's binary directory from the rest of the existing directories. DO NOT DELETE any existing entries; otherwise, some existing applications may not run.
Variable name : PATH
Variable value : c:\Program Files\Java\jdk1.8.0_xx\bin;[existing entries...]
