$.ajax withot jquery code example
Example 1: $.ajax({
<!doctype html>
<html lang="en">
<head>
<meta charset="utf-8">
<title>jQuery.post demo</title>
<script src="https://code.jquery.com/jquery-1.10.2.js"></script>
</head>
<body>
<form action="/" id="searchForm">
<input type="text" name="s" placeholder="Search...">
<input type="submit" value="Search">
</form>
<!-- the result of the search will be rendered inside this div -->
<div id="result"></div>
<script>
$( "#searchForm" ).submit(function( event ) {
event.preventDefault();
var $form = $( this ),
term = $form.find( "input[name='s']" ).val(),
url = $form.attr( "action" );
var posting = $.post( url, { s: term } );
posting.done(function( data ) {
var content = $( data ).find( "#content" );
$( "#result" ).empty().append( content );
});
});
</script>
</body>
</html>
Example 2: $.ajax example
class DB {
private $host = 'localhost';
private $user = 'root';
private $password = '';
private $db_name = 'library';
public $conn;
public function connect() {
$this-> conn = new mysqli($this-> host, $this-> user, $this-> password, $this-> db_name);
return $this -> conn;
}
}