JavaScript: Compare the structure of two JSON objects while ignoring their values

This is an elegant solution. You could do it simple like this:

var equal = true;
for (i in object1)
    if (!object2.hasOwnProperty(i))
        equal = false;

If the two elements have the same properties, then, the var equal must remain true.

And as function:

function compareObjects(object1, object2){
    var equal = true;
    for (i in object1)
        if (!object2.hasOwnProperty(i))
            equal = false;
    return equal;
}