distance calculator based on lat long in c# code example

Example 1: distance between two points latitude longitude c#

float DeltaFi = (float)ConvertToRadians(lat2 - lat1);
float DeltaLambda = (float)ConvertToRadians(lon2 - lon1);
float a = Mathf.Sin(DeltaFi / 2) * Mathf.Sin(DeltaFi / 2) + Mathf.Cos(fi1) * Mathf.Cos(fi2) * Mathf.Sin(DeltaLambda / 2) * Mathf.Sin(DeltaLambda / 2);
float c = 2 * Mathf.Atan2(Mathf.Sqrt(a), Mathf.Sqrt(1 - a));
float distance = earthD * c;

Example 2: calculate distance using latitude and longitude c#

public static double DistanceTo(double lat1, double lon1, double lat2, double lon2, char unit = 'K')
{
    double rlat1 = Math.PI*lat1/180;
    double rlat2 = Math.PI*lat2/180;
    double theta = lon1 - lon2;
    double rtheta = Math.PI*theta/180;
    double dist =
        Math.Sin(rlat1)*Math.Sin(rlat2) + Math.Cos(rlat1)*
        Math.Cos(rlat2)*Math.Cos(rtheta);
    dist = Math.Acos(dist);
    dist = dist*180/Math.PI;
    dist = dist*60*1.1515;

    switch (unit)
    {
        case 'K': //Kilometers -> default
            return dist*1.609344;
        case 'N': //Nautical Miles 
            return dist*0.8684;
        case 'M': //Miles
            return dist;
    }

    return dist;
}