JavaScript: How to pass object by value?

Here is clone function that will perform deep copy of the object:

function clone(obj){
    if(obj == null || typeof(obj) != 'object')
        return obj;

    var temp = new obj.constructor(); 
    for(var key in obj)
        temp[key] = clone(obj[key]);

    return temp;
}

Now you can you use like this:

(function(x){
    var obj = clone(x);
    obj.foo = 'foo';
    obj.bar = 'bar';
})(o)

Check out this answer https://stackoverflow.com/a/5344074/746491 .

In short, JSON.parse(JSON.stringify(obj)) is a fast way to copy your objects, if your objects can be serialized to json.

Use Object.assign()

Example:

var a = {some: object};
var b = new Object;
Object.assign(b, a);
// b now equals a, but not by association.

A cleaner example that does the same thing:

var a = {some: object};
var b = Object.assign({}, a);
// Once again, b now equals a.

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Object/assign

Not really.

Depending on what you actually need, one possibility may be to set o as the prototype of a new object.

var o = {};
(function(x){
    var obj = Object.create( x );
    obj.foo = 'foo';
    obj.bar = 'bar';
})(o);

alert( o.foo ); // undefined

So any properties you add to obj will be not be added to o. Any properties added to obj with the same property name as a property in o will shadow the o property.

Of course, any properties added to o will be available from obj if they're not shadowed, and all objects that have o in the prototype chain will see the same updates to o.

Also, if obj has a property that references another object, like an Array, you'll need to be sure to shadow that object before adding members to the object, otherwise, those members will be added to obj, and will be shared among all objects that have obj in the prototype chain.

var o = {
    baz: []
};
(function(x){
    var obj = Object.create( x );

    obj.baz.push( 'new value' );

})(o);

alert( o.baz[0] );  // 'new_value'

Here you can see that because you didn't shadow the Array at baz on o with a baz property on obj, the o.baz Array gets modified.

So instead, you'd need to shadow it first:

var o = {
    baz: []
};
(function(x){
    var obj = Object.create( x );

    obj.baz = [];
    obj.baz.push( 'new value' );

})(o);

alert( o.baz[0] );  // undefined