java how to check if element is in array code example

Example 1: Check if an array contains an element java

import java.util.Arrays;

// For String
String[] array = {"Boto", "Nesto", "Lepta"};
String toSearch = "Nesto";

// Inline
if (Arrays.toString(array).contains(toSearch)) {
	// Do something if it's found
}

// Multi line
String strArray = Array.toString(array);
if (strArray.contains(toSearch)) {
	// Do your thing
}

// Different elements
int[] numbers = {1, 2, 3, 4, 5, 6, 7, 8, 9, 0};
int number = 5;

String checker = Arrays.toString(numbers);

// The toString of int in some cases can happen without explicitly saying so
// In this example we convert both
if (checker.contains(Integer.toString(number)) {
	// Found.     
}

Example 2: java check if element exists in array

package com.mkyong.core;

import java.util.Arrays;
import java.util.List;

public class StringArrayExample1 {

    public static void main(String[] args) {

        String[] alphabet = new String[]{"A", "B", "C"};

        // Convert String Array to List
        List<String> list = Arrays.asList(alphabet);
        
        if(list.contains("A")){
            System.out.println("Hello A");
        }

    }

}
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Example 3: how to find contain elements in array in java

public class Contains {

    public static void main(String[] args) {
        int[] num = {1, 2, 3, 4, 5};
        int toFind = 3;
        boolean found = false;

        for (int n : num) {
            if (n == toFind) {
                found = true;
                break;
            }
        }

        if(found)
            System.out.println(toFind + " is found.");
        else
            System.out.println(toFind + " is not found.");
    }
}