javascript find in array without returning undefined code example

Example 1: find in array of objects javascript

let arr = [
    { name:"string 1", value:"this", other: "that" },
    { name:"string 2", value:"this", other: "that" }
];

let obj = arr.find(o => o.name === 'string 1');

console.log(obj);

Example 2: javascript find

const inventory = [
  {name: 'apples', quantity: 2},
  {name: 'cherries', quantity: 8}
  {name: 'bananas', quantity: 0},
  {name: 'cherries', quantity: 5}
  {name: 'cherries', quantity: 15}
  
];

const result = inventory.find( ({ name }) => name === 'cherries' );

console.log(result) // { name: 'cherries', quantity: 5 }

Example 3: javascript array.find

const array1 = [5, 12, 8, 130, 44];

const found = array1.find(element => element > 10);

console.log(found);
// expected output: 12