javascript get params from query string code example
Example 1: js get query param
const queryString = window.location.search;
const parameters = new URLSearchParams(queryString);
const value = parameters.get('key');
Example 2: javascript reading query parameter
const urlParams = new URLSearchParams(window.location.search);
const firstName = urlParams.get('fname');
Example 3: javascript get query parameter
function getUrlParameter(name) {
name = name.replace(/[\[]/, '\\[').replace(/[\]]/, '\\]');
var regex = new RegExp('[\\?&]' + name + '=([^&#]*)');
var results = regex.exec(location.search);
return results === null ? '' : decodeURIComponent(results[1].replace(/\+/g, ' '));
};
Example 4: how to get query param in javascript
const urlParams = new URLSearchParams(window.location.search);
const myParam = urlParams.get('myParam');
Example 5: javascript get params from query strinG
let parameters = 'www.goole.com?code=1232';
var search = parameters.split('?')[1];
parameters = JSON.parse('{"' + decodeURI(search).replace(/"/g, '\\"').replace(/&/g, '","').replace(/=/g,'":"') + '"}')
alert(JSON.stringify(parameters))
output : {code:1232}:
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IF YOU WANT TO USE URL FROM BROWSER THEN USE
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const parameters = window.location.search;
var search = parameters.split('?')[1];
parameters = JSON.parse('{"' + decodeURI(search).replace(/"/g, '\\"').replace(/&/g, '","').replace(/=/g,'":"') + '"}')
alert(JSON.stringify(parameters))
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ANOTHER WAY IS ======================[[
const queryString = window.location.search;
const parameters = new URLSearchParams(queryString);
const value = parameters.get('key');