JavaScript numbers to Words
Your problem is already solved but I am posting another way of doing it just for reference.
The code was written to be tested on node.js, but the functions should work fine when called within the browser. Also, this only handles the range [0,1000000], but can be easily adapted for bigger ranges.
// actual conversion code starts here
var ones = ['', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight', 'nine'];
var tens = ['', '', 'twenty', 'thirty', 'forty', 'fifty', 'sixty', 'seventy', 'eighty', 'ninety'];
var teens = ['ten', 'eleven', 'twelve', 'thirteen', 'fourteen', 'fifteen', 'sixteen', 'seventeen', 'eighteen', 'nineteen'];
function convert_millions(num) {
if (num >= 1000000) {
return convert_millions(Math.floor(num / 1000000)) + " million " + convert_thousands(num % 1000000);
} else {
return convert_thousands(num);
}
}
function convert_thousands(num) {
if (num >= 1000) {
return convert_hundreds(Math.floor(num / 1000)) + " thousand " + convert_hundreds(num % 1000);
} else {
return convert_hundreds(num);
}
}
function convert_hundreds(num) {
if (num > 99) {
return ones[Math.floor(num / 100)] + " hundred " + convert_tens(num % 100);
} else {
return convert_tens(num);
}
}
function convert_tens(num) {
if (num < 10) return ones[num];
else if (num >= 10 && num < 20) return teens[num - 10];
else {
return tens[Math.floor(num / 10)] + " " + ones[num % 10];
}
}
function convert(num) {
if (num == 0) return "zero";
else return convert_millions(num);
}
//end of conversion code
//testing code begins here
function main() {
var cases = [0, 1, 2, 7, 10, 11, 12, 13, 15, 19, 20, 21, 25, 29, 30, 35, 50, 55, 69, 70, 99, 100, 101, 119, 510, 900, 1000, 5001, 5019, 5555, 10000, 11000, 100000, 199001, 1000000, 1111111, 190000009];
for (var i = 0; i < cases.length; i++) {
console.log(cases[i] + ": " + convert(cases[i]));
}
}
main();
I know this problem had solved 3 years ago. I am posting this SPECIALLY FOR INDIAN DEVELOPERS
After spending some time in googling and playing with others code i made a quick fix and reusable function works well for numbers upto 99,99,99,999. use : number2text(1234.56);
will return ONE THOUSAND TWO HUNDRED AND THIRTY-FOUR RUPEE AND FIFTY-SIX PAISE ONLY
. enjoy !
function number2text(value) {
var fraction = Math.round(frac(value)*100);
var f_text = "";
if(fraction > 0) {
f_text = "AND "+convert_number(fraction)+" PAISE";
}
return convert_number(value)+" RUPEE "+f_text+" ONLY";
}
function frac(f) {
return f % 1;
}
function convert_number(number)
{
if ((number < 0) || (number > 999999999))
{
return "NUMBER OUT OF RANGE!";
}
var Gn = Math.floor(number / 10000000); /* Crore */
number -= Gn * 10000000;
var kn = Math.floor(number / 100000); /* lakhs */
number -= kn * 100000;
var Hn = Math.floor(number / 1000); /* thousand */
number -= Hn * 1000;
var Dn = Math.floor(number / 100); /* Tens (deca) */
number = number % 100; /* Ones */
var tn= Math.floor(number / 10);
var one=Math.floor(number % 10);
var res = "";
if (Gn>0)
{
res += (convert_number(Gn) + " CRORE");
}
if (kn>0)
{
res += (((res=="") ? "" : " ") +
convert_number(kn) + " LAKH");
}
if (Hn>0)
{
res += (((res=="") ? "" : " ") +
convert_number(Hn) + " THOUSAND");
}
if (Dn)
{
res += (((res=="") ? "" : " ") +
convert_number(Dn) + " HUNDRED");
}
var ones = Array("", "ONE", "TWO", "THREE", "FOUR", "FIVE", "SIX","SEVEN", "EIGHT", "NINE", "TEN", "ELEVEN", "TWELVE", "THIRTEEN","FOURTEEN", "FIFTEEN", "SIXTEEN", "SEVENTEEN", "EIGHTEEN","NINETEEN");
var tens = Array("", "", "TWENTY", "THIRTY", "FOURTY", "FIFTY", "SIXTY","SEVENTY", "EIGHTY", "NINETY");
if (tn>0 || one>0)
{
if (!(res==""))
{
res += " AND ";
}
if (tn < 2)
{
res += ones[tn * 10 + one];
}
else
{
res += tens[tn];
if (one>0)
{
res += ("-" + ones[one]);
}
}
}
if (res=="")
{
res = "zero";
}
return res;
}
JavaScript is parsing the group of 3 numbers as an octal number when there's a leading zero digit. When the group of three digits is all zeros, the result is the same whether the base is octal or decimal.
But when you give JavaScript '009' (or '008'), that's an invalid octal number, so you get zero back.
If you had gone through the whole set of numbers from 190,000,001 to 190,000,010 you'd hav seen JavaScript skip '...,008' and '...,009' but emit 'eight' for '...,010'. That's the 'Eureka!' moment.
Change:
for (j = 0; j < finlOutPut.length; j++) {
finlOutPut[j] = triConvert(parseInt(finlOutPut[j]));
}
to
for (j = 0; j < finlOutPut.length; j++) {
finlOutPut[j] = triConvert(parseInt(finlOutPut[j],10));
}
Code also kept on adding commas after every non-zero group, so I played with it and found the right spot to add the comma.
Old:
for (b = finlOutPut.length - 1; b >= 0; b--) {
if (finlOutPut[b] != "dontAddBigSufix") {
finlOutPut[b] = finlOutPut[b] + bigNumArry[bigScalCntr] + ' , ';
bigScalCntr++;
}
else {
//replace the string at finlOP[b] from "dontAddBigSufix" to empty String.
finlOutPut[b] = ' ';
bigScalCntr++; //advance the counter
}
}
//convert The output Arry to , more printable string
for(n = 0; n<finlOutPut.length; n++){
output +=finlOutPut[n];
}
New:
for (b = finlOutPut.length - 1; b >= 0; b--) {
if (finlOutPut[b] != "dontAddBigSufix") {
finlOutPut[b] = finlOutPut[b] + bigNumArry[bigScalCntr]; // <<<
bigScalCntr++;
}
else {
//replace the string at finlOP[b] from "dontAddBigSufix" to empty String.
finlOutPut[b] = ' ';
bigScalCntr++; //advance the counter
}
}
//convert The output Arry to , more printable string
var nonzero = false; // <<<
for(n = 0; n<finlOutPut.length; n++){
if (finlOutPut[n] != ' ') { // <<<
if (nonzero) output += ' , '; // <<<
nonzero = true; // <<<
} // <<<
output +=finlOutPut[n];
}