open folder shift rightclick open with android studio code example

Example: open folder shift rightclick open with android studio

Open windows registry by pressing Window + r type regedit and 
enter Run the registry editor 
Go to HKEY_CLASSES_ROOT\Directory\shell 
Right click on shell create a new key and 
name it as you want to see the entry in context menu 
then right click on the created file and create a new key 
and name it as command in lower case Click command 
and on right side pane you will see a key named as 
default Double click the default entry 
and enter the path of application exe file as the value. 
You need enter a spacebar then %1 at the end of application path
that you entered as a value of default value. It worked for me.