Javascript Reduce an empty array

The second parameter is for initial value.

[].reduce(function(previousValue, currentValue){
  return Number(previousValue) + Number(currentValue);
}, 0);

or using ES6:

[].reduce( (previousValue, currentValue) => previousValue + currentValue, 0);

Both behaviors are according to the spec.

You cannot reduce an empty array unless you explicitly provide an initial "accumulated" value as the second argument:

If no initialValue was provided, then previousValue will be equal to the first value in the array and currentValue will be equal to the second. It is a TypeError if the array contains no elements and initialValue is not provided.

If the array has at least one element then providing an initial value is optional. However, if one is not provided then the first element of the array is used as the initial value and reduce continues to process the rest of the array elements by invoking your callback. In your case the array only contains a single element, so that element becomes the initial value and also final value, since there are no more elements to be processed through the callback.