Reverse a string in JavaScript without using inbuilt function code example

Example 1: javascript reverse a string

function reverseString(s){
    return s.split("").reverse().join("");
}
reverseString("Hello");//"olleH"

Example 2: javascrip reverse text

//more compact way: 
"my example text".split("").reverse().join("");

Example 3: javascript reverse string without reverse method

function reverse(str){  
  let reversed = "";      
   for (var i = str.length - 1; i >= 0; i--){         
     reversed += str[i];  
   }     
  return reversed;
}

Example 4: reverse string javascript

const reverse = (str) => str.split("").reverse().join("");

Example 5: reverse a string program in javascript

function reverseString(str) {
    var newString = "";
    for (var i = str.length - 1; i >= 0; i--) {
        newString += str[i];
    }
    return newString;
}
reverseString('hello');

Example 6: how to reverse a string in javascript without using reverse method

function reverseString(str) {
  if (str === "") // This is the terminal case that will end the recursion
    return "";
  
  else
    return reverseString(str.substr(1)) + str.charAt(0);
/* 
First Part of the recursion method
You need to remember that you won’t have just one call, you’ll have several nested calls

Each call: str === "?"        	                  reverseString(str.subst(1))     + str.charAt(0)
1st call – reverseString("Hello")   will return   reverseString("ello")           + "h"
2nd call – reverseString("ello")    will return   reverseString("llo")            + "e"
3rd call – reverseString("llo")     will return   reverseString("lo")             + "l"
4th call – reverseString("lo")      will return   reverseString("o")              + "l"
5th call – reverseString("o")       will return   reverseString("")               + "o"

Second part of the recursion method
The method hits the if condition and the most highly nested call returns immediately

5th call will return reverseString("") + "o" = "o"
4th call will return reverseString("o") + "l" = "o" + "l"
3rd call will return reverseString("lo") + "l" = "o" + "l" + "l"
2nd call will return reverserString("llo") + "e" = "o" + "l" + "l" + "e"
1st call will return reverserString("ello") + "h" = "o" + "l" + "l" + "e" + "h" 
*/
}
reverseString("hello");