submit form with file upload using ajax php code example

Example 1: file upload in php through ajax

**1. index.php**
<body>
    <span id="msg" style="color:red"></span><br/>
    <input type="file" id="photo"><br/>
  <script type="text/javascript" src="jquery-3.2.1.min.js"></script>
  <script type="text/javascript">
    $(document).ready(function(){
      $(document).on('change','#photo',function(){
        var property = document.getElementById('photo').files[0];
        var image_name = property.name;
        var image_extension = image_name.split('.').pop().toLowerCase();

        if(jQuery.inArray(image_extension,['gif','jpg','jpeg','']) == -1){
          alert("Invalid image file");
        }

        var form_data = new FormData();
        form_data.append("file",property);
        $.ajax({
          url:'upload.php',
          method:'POST',
          data:form_data,
          contentType:false,
          cache:false,
          processData:false,
          beforeSend:function(){
            $('#msg').html('Loading......');
          },
          success:function(data){
            console.log(data);
            $('#msg').html(data);
          }
        });
      });
    });
  </script>
</body>

**2.upload.php**
<?php
if($_FILES['file']['name'] != ''){
    $test = explode('.', $_FILES['file']['name']);
    $extension = end($test);    
    $name = rand(100,999).'.'.$extension;

    $location = 'uploads/'.$name;
    move_uploaded_file($_FILES['file']['tmp_name'], $location);

    echo '<img src="'.$location.'" height="100" width="100" />';
}

Example 2: file upload in php through ajax

var formData = new FormData($("#YOUR_FORM_ID")[0]);
$.ajax({
    url: "upload.php",
    type: "POST",
    data : formData,
    processData: false,
    contentType: false,
    beforeSend: function() {

    },
    success: function(data){




    },
    error: function(xhr, ajaxOptions, thrownError) {
       console.log(thrownError + "\r\n" + xhr.statusText + "\r\n" + xhr.responseText);
    }
});