jQuery Clone table row

Your problem is that your insertAfter:

.insertAfter(".tr_clone")

inserts after every .tr_clone:

the matched set of elements will be inserted after the element(s) specified by this parameter.

You probably just want to use after on the row you're duplicating. And a little .find(':text').val('') will clear the cloned text inputs; something like this:

var $tr    = $(this).closest('.tr_clone');
var $clone = $tr.clone();
$clone.find(':text').val('');
$tr.after($clone);

Demo: http://jsfiddle.net/ambiguous/LAECx/ or for a modern jQuery: http://jsfiddle.net/ambiguous/LAECx/3274/

I'm not sure which input should end up with the focus so I've left that alone.

The code below will clone last row and add after last row in table:

var $tableBody = $('#tbl').find("tbody"),
$trLast = $tableBody.find("tr:last"),
$trNew = $trLast.clone();

$trLast.after($trNew);

Working example : http://jsfiddle.net/kQpfE/2/

Here you go:

$( table ).delegate( '.tr_clone_add', 'click', function () {
    var thisRow = $( this ).closest( 'tr' )[0];
    $( thisRow ).clone().insertAfter( thisRow ).find( 'input:text' ).val( '' );
});

Live demo: http://jsfiddle.net/RhjxK/4/

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Update: The new way of delegating events in jQuery is

$(table).on('click', '.tr_clone_add', function () { … });