js find second max occurrence of a number in an array code example
Example 1: find second largest number in array javascript
var secondMax = function (arr){
var max = Math.max.apply(null, arr), // get the max of the array
maxi = arr.indexOf(max);
arr[maxi] = -Infinity; // replace max in the array with -infinity
var secondMax = Math.max.apply(null, arr); // get the new max
arr[maxi] = max;
return secondMax;
};
Example 2: find second max element in array in 1 iteration
/**
* C program to find second largest number in an array
*/
#include <stdio.h>
#include <limits.h> // For INT_MIN
#define MAX_SIZE 1000 // Maximum array size
int main()
{
int arr[MAX_SIZE], size, i;
int max1, max2;
/* Input size of the array */
printf("Enter size of the array (1-1000): ");
scanf("%d", &size);
/* Input array elements */
printf("Enter elements in the array: ");
for(i=0; i<size; i++)
{
scanf("%d", &arr[i]);
}
max1 = max2 = INT_MIN;
/*
* Check for first largest and second
*/
for(i=0; i<size; i++)
{
if(arr[i] > max1)
{
/*
* If current element of the array is first largest
* then make current max as second max
* and then max as current array element
*/
max2 = max1;
max1 = arr[i];
}
else if(arr[i] > max2 && arr[i] < max1)
{
/*
* If current array element is less than first largest
* but is greater than second largest then make it
* second largest
*/
max2 = arr[i];
}
}
printf("First largest = %d\n", max1);
printf("Second largest = %d", max2);
return 0;
}