json_decode to array

This is a late contribution, but there is a valid case for casting json_decode with (array).
Consider the following:

$jsondata = '';
$arr = json_decode($jsondata, true);
foreach ($arr as $k=>$v){
    echo $v; // etc.
}

If $jsondata is ever returned as an empty string (as in my experience it often is), json_decode will return NULL, resulting in the error Warning: Invalid argument supplied for foreach() on line 3. You could add a line of if/then code or a ternary operator, but IMO it's cleaner to simply change line 2 to ...

$arr = (array) json_decode($jsondata,true);

... unless you are json_decodeing millions of large arrays at once, in which case as @TCB13 points out, performance could be negatively effected.


Just in case you are working on php less then 5.2 you can use this resourse.

http://techblog.willshouse.com/2009/06/12/using-json_encode-and-json_decode-in-php4/

http://mike.teczno.com/JSON/JSON.phps


try this

$json_string = 'http://www.domain.com/jsondata.json';
$jsondata = file_get_contents($json_string);
$obj = json_decode($jsondata,true);
echo "<pre>";
print_r($obj);

As per the documentation, you need to specify true as the second argument if you want an associative array instead of an object from json_decode. This would be the code:

$result = json_decode($jsondata, true);

If you want integer keys instead of whatever the property names are:

$result = array_values(json_decode($jsondata, true));

However, with your current decode you just access it as an object:

print_r($obj->Result);

Tags:

Php

Arrays

Json