JSON encode MySQL results

$sth = mysqli_query($conn, "SELECT ...");
$rows = array();
while($r = mysqli_fetch_assoc($sth)) {
    $rows[] = $r;
}
print json_encode($rows);

The function json_encode needs PHP >= 5.2 and the php-json package - as mentioned here

NOTE: mysql is deprecated as of PHP 5.5.0, use mysqli extension instead http://php.net/manual/en/migration55.deprecated.php.


Try this, this will create your object properly

 $result = mysql_query("SELECT ...");
 $rows = array();
   while($r = mysql_fetch_assoc($result)) {
     $rows['object_name'][] = $r;
   }

 print json_encode($rows);

http://www.php.net/mysql_query says "mysql_query() returns a resource".

http://www.php.net/json_encode says it can encode any value "except a resource".

You need to iterate through and collect the database results in an array, then json_encode the array.

Tags:

Mysql

Php

Json