keep only alphabet characters
Using a stream:
List<Character> letters = string.chars()
.mapToObj(i -> (char) i)
.filter(Character::isAlphabetic)
.collect(Collectors.toList());
You can use String.replaceAll(regex, replacement)
with the regex [^A-Za-z]+
like this:
String newstr = "Word#$#$% Word 1234".replaceAll("[^A-Za-z]+", "");
// newstr will become WordWord
Edit: Although OP hasn't mentioned anything about unicode characters
but since @Joey has made a comment and if at all there a requirement to keep unicode characters then \\P{L}+
regex should be used like this:
String newstr = "Word#$#$% Word λ1234ä, ñ, ж".replaceAll("\\P{L}+", "");
// newstr will become WordWordλäñж
public static void main(String[] args) {
String input = "Word#$#$% Word 1234";
String extract = input.replaceAll("[^a-zA-Z]+", "");
System.out.println(extract);
}
output:
WordWord
You can use Character.isLetter(char c)
in Character class like this
String s = "Word#$#$% Word 1234";
StringBuffer r = new StringBuffer();
for (int k = 0; k < s.length(); k++) {
if(Character.isLetter(s.charAt(k)))
r.append(s.charAt(k));
}
System.out.println("Result " + r.toString());