Lambda Expression Tree Parsing
Remember that when you're dealing with the lambda expression as an expression tree, you don't have executable code. Rather you have a tree of expression elements, that make up the expression you wrote.
Charlie Calvert has a good post that discusses this in detail. Included is an example of using an expression visualiser for debugging expressions.
In your case, to get the value of the righthand side of the equality expression, you'll need to create a new lambda expression, compile it and then invoke it.
I've hacked together a quick example of this - hope it delivers what you need.
public class Class1
{
public string Selection { get; set; }
public void Sample()
{
Selection = "Example";
Example<Book, bool>(p => p.Title == Selection);
}
public void Example<T,TResult>(Expression<Func<T,TResult>> exp)
{
BinaryExpression equality = (BinaryExpression)exp.Body;
Debug.Assert(equality.NodeType == ExpressionType.Equal);
// Note that you need to know the type of the rhs of the equality
var accessorExpression = Expression.Lambda<Func<string>>(equality.Right);
Func<string> accessor = accessorExpression.Compile();
var value = accessor();
Debug.Assert(value == Selection);
}
}
public class Book
{
public string Title { get; set; }
}
To get the actual value, you need to apply the logic of the expression tree to whatever context you've got.
The whole point of expression trees is that they represent the logic as data rather than evaluating the expression. You'll need to work out what the lambda expression truly means. That may mean evaluating some parts of it against local data - you'll need to decide that for yourself. Expression trees are very powerful, but it's not a simple matter to parse and use them. (Ask anyone who's written a LINQ provider... Frans Bouma has bemoaned the difficulties several times.)