Lambda inside lambda

You can use an inner lambda to return another function, based on the outer parameters:

mul = lambda x: (lambda y: y * x)
times4 = mul(4)
print times4(2)

You aren't actually calling the inner lambda:

p = lambda x: (lambda x: x%2)(x)/2

Note in Python 2 this example will always return 0 since the remainder from dividing by 2 will be either 0 or 1 and integer-dividing that result by 2 will result in a truncated 0.